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The spin-only magnetic moment value of an octahedral complex among \mathrm{CoCl}_{3} \cdot 4 \mathrm{NH}_{3}$, $\mathrm{NiCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}$ and $\mathrm{PtCl}_{4} \cdot 2 \mathrm{HCl}, which upon reaction with excess of \mathrm{AgNO}_{3}$ gives 2 moles of $\mathrm{AgCl} is ____________B.M. (Nearest Integer)

Option: 1

3


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

The given complexes exist as 

\mathrm{CoCl _{3} \cdot 4 NH _{3} : [Co(NH_3)_4Cl_2]Cl}

\mathrm{NiCl _{2} \cdot 6 H _{2} O: \left[ Ni \left( H _{2} O \right)_{6}\right] Cl _{2}}

\mathrm{PtCl _{4} \cdot 2 HCl : H _{2}\left[ PtCl _{6}\right]}

Among the given complexes,

\mathrm{NiCl_{2}\cdot 6H_{2}O} is an octahedral complex which gives 2 moles of  \mathrm{AgCl} upon reaction with excess of \mathrm{AgNO_{3}}.

\mathrm{\left [ Ni \left ( H_{2}O \right )_{6}\right ]Cl_{2}\overset{2AgNO_{3}}{\longrightarrow}2\, AgCl\, \downarrow+\left [ Ni\left ( H_{2}O \right )_{6} \right ]\left ( NO_{3} \right )_{2}}

\mathrm{Ni} is in +2 oxidation state.

Configuration

No.of unpaired \mathrm{e^-= 2.}

magnetic moment \mathrm{= \sqrt{n\left ( n+2 \right )}\: B.M}
                              \mathrm{= \sqrt{2\left ( 2+4 \right )}\: BM}
                              \mathrm{= 2.84\approx 3\: BM}

Hence 3 is answer

Posted by

Nehul

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