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  • The spin-only magnetic moment value of the most basic oxide of vanadium among <img alt="\mathrm{V}_{2} \mathrm{O}_{3}$, $\mathrm{V}_{2} \mathrm{O}_{4}$ and $\mathrm{V}_{2} \mathrm{O}_{5}" src="http

The spin-only magnetic moment value of the most basic oxide of vanadium among \mathrm{V}_{2} \mathrm{O}_{3}$, $\mathrm{V}_{2} \mathrm{O}_{4}$ and $\mathrm{V}_{2} \mathrm{O}_{5} is_____________ B.M. (Nearest integer)

Option: 1

3


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

As we have learnt, 

Oxides with lesser oxidation state of the metal ion is more basic.

Thus, the most basic oxide among the given ones is \mathrm{ V_{2}O_{3}} and the oxidation state of \mathrm{ V} is +3.

\mathrm{\therefore V^{+3}\rightarrow \left [ Ar \right ]3d^{2}}

no.of unpaired electrons \mathrm{= 2.}

\mathrm{\therefore \; magnetic \; moment,\mu = \sqrt{n\left ( n+2 \right )}\; \; B. M.}
                                                    \mathrm{= \sqrt{2\left ( 2+2 \right )}\; B.M}
                                                     \mathrm{= 2.84 \approx 3\; B.M.}

Hence, 3 is the answer.

Posted by

Kuldeep Maurya

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