Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The straight lines \mathrm{x+y-4=0,3 x+y-4=0} \mathrm{and \: x+3 y-4=0} form a triangle which is
 

Option: 1

isosceles triangle
 


Option: 2

equilateral
 


Option: 3

right angled
 


Option: 4

none of these


Answers (1)

best_answer

The given equation are

\mathrm{ x+y-4=0 }        ..(i)

\mathrm{ 3 x+y-4=0 }     .......(ii)

\mathrm{ x+3 y-4=0 }    .......(iii)

Solving (i) & (ii) we get the co-ordinate of \mathrm{ \mathrm{A}(0,4) }

Solving (ii) & (iii) we get the coordinate of \mathrm{ \mathrm{B}(1,1)} and solving (iii) \& (i) we get the co-ordinate \mathrm{ \mathrm{C}(4,0)}

\mathrm{ \mathrm{AB}=\sqrt{10}=\mathrm{BC}, \mathrm{CA}=4 \sqrt{2} }

Hence \Delta is isosceles triangle

Hence option 1 is correct.

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JoSAA 2025 reconstituted; NIT Rourkela to coordinate BTech counselling for IITs, NITs, IIITs
anam-khan

JEE Main 2025: BTech Information Technology cut-offs at NITs; know opening, closing ranks
anam-khan

JEE Main 2025: BTech Computer Science Engineering cut-offs at NITs went up this year

Latest Question