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The susceptibility of a paramagnetic material is \mathrm{99}. The permeability of the material in \mathrm{Wb/A-m}, is :

( Permeability of free space \mathrm{\mu_{0}=4\pi\times 10^{-7}Wb/A-m} )

Option: 1

\mathrm{4\pi \times 10^{-7}}


Option: 2

\mathrm{4\pi \times 10^{-4}}


Option: 3

\mathrm{4\pi \times 10^{-5}}


Option: 4

\mathrm{4\pi \times 10^{-6}}


Answers (1)

best_answer

\mathrm{\mu_{r}=1+\lambda} \\                          \mathrm{ \lambda \rightarrow \text { susceptibility }}

\mathrm{\frac{\mu}{\mu_{0}}=1+99 } \\                       \mathrm{\mu _{r} \rightarrow \text { relatine permeability }}

\mathrm{\mu=100 \times \mu_{o} =100 \times 4 \pi \times 10^{7}} \\

     \mathrm{}=4 \pi \times 10^{-5}

Hence the correct answer is option 3

Posted by

Irshad Anwar

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