The tangent at a point P on the hyperbola passes through the point (0,-b) and the normal at P passes through the point
. Then the square of eccentricity of the hyperbola is
5
2
9
8
The equation of tangent at is
It passes through (0,-b). So,
The equation of normal is
which passes through (2 a \sqrt{2}, 0). Hence,
Now, lies on the hyperbola. Therefore,
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