The tangents to the curve at its points of intersection with the line x-y=3, intersect at the point Then m-n is
-7
-3
7
3
The given curve is Y
and the given line is x – y = 3.
Now, put x – 2 = X and y + 1 = Y. Equation of curve becomes
.....[i]
and equation of line becomes Y = X ...(ii)
So, the points of intersection of (i) and (ii) are O(0, 0) and
A(1, 1).
Now, tangent at O(0, 0) to the curve is X-axis, i.e.,
Y = 0.
Equation of tangent at A(1, 1) to the curve is
Y + 1 = 2X.
Hence, the point of intersection of the given curve
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