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  • The tempreaure coefficient for the saponification of ethyl acetate is 1.75 calculate the activation energy of thr reaction

The temperature coefficient for the saponification of ethyl acetate is 1.75. Calculate the activation energy of the reaction.

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$Q = e^{\frac{E_a}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right)}$ 

$\ln Q = \frac{E_a}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right)$
$\text{For a temperature increase of } \Delta{T} = 10$
$\text{Assume } T_1 = 298 \, \text{K} \text{ and } T_2 = T_1 + 10 = 308 \, \text{K}$

$\ln Q = \frac{E_a}{R} \left( \frac{1}{298} - \frac{1}{308} \right)$

$\ln 1.75 = \frac{E_a}{8.314} \left( \frac{1}{298} - \frac{1}{308} \right)$

$E_a = \frac{\ln 1.75 \times 8.314}{\left( \frac{1}{298} - \frac{1}{308} \right)}$=42.7 kJ/mol

Posted by

Saniya Khatri

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