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The time for the half-life period of a certain reaction, \mathrm{A \rightarrow Products} in 1 h. When the initial concentration of the reactant A is 2.0 mol L-1, how much time (in hour) does it take for its concentration to come from 0.50 to 0.25 mol L-1, if it is a zero-order reaction?

Option: 1

0.25


Option: 2

0.5


Option: 3

4


Option: 4

1


Answers (1)

best_answer

\begin{array}{l}{\text {Half-life for a zero order reaction is given by }} \\ {t_{1 / 2}=\frac{\left[A_{0}\right]}{2 k}} \\ { \text {[where }\left.\left[A_{0}\right]=\text { initial concentration of reactant }\right]} \end{array}

\\\\ {\Rightarrow \quad k=\frac{\left[A_{0}\right]}{2 t_{1 / 2}}=\frac{2.0 \mathrm{\: mol} \mathrm{L}^{-1}}{2 \times 1 \mathrm{h}}=1.0 \mathrm{\: mol} \mathrm{\: L}^{-1} \mathrm{h}^{-1}}


\begin{array}{l}{\text {Rate constant for a zero-order reaction is given by }}\\ \\ {t=\frac{1}{k}\left[\left(A_{0}\right)-(A)\right]}\end{array}

\\\\ {t=\frac{(0.50)-(0.25) \mathrm{\: mol}L^{-1}}{1 \mathrm{\: mol\: } \mathrm{L}^{-1} \mathrm{h}^{-1}} \Rightarrow t=0.25 \mathrm{\: h}}

 

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Rishi

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