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  •  The total charge on the system of capacitors <img alt="\mathrm{C_{1}=1 \; \mu \; \! \mathrm{F}, C_{2}=2 \; \mu \mathrm{F}, C_{3}=4 \; \mu \mathrm{F} \text { and } C_{4}=3\; \mu \mathrm{F

 The total charge on the system of capacitors \mathrm{C_{1}=1 \; \mu \; \! \mathrm{F}, C_{2}=2 \; \mu \mathrm{F}, C_{3}=4 \; \mu \mathrm{F} \text { and } C_{4}=3\; \mu \mathrm{F}} connected in parallel is : 

 (Assume a battery of  \mathrm{20 \mathrm{~V} } is connected to the combination) 

Option: 1

\mathrm{200\; \mu C}


Option: 2

\mathrm{200\; C}


Option: 3

\mathrm{10\; \mu C}


Option: 4

\mathrm{10\; C}


Answers (1)

best_answer

\mathrm{C_{e q} =C_1+C_2+C_3+C_4 }

        \mathrm{=1+2+4+3 }

\mathrm{C_{e q} =10 \mu \mathrm{F} }

\mathrm{q= \left ( C_{e q} \right )V}

    \mathrm{=(10 \mathrm{mF}) \times 20 \mathrm{~V} }

\mathrm{q =200 \mathrm{\mu C}}

Hence (1) is correct option.

Posted by

rishi.raj

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