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The total number of unpaired electrons present in the complex K3[Cr(oxalate)3] is __________.
 

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Given complex \mathrm{K}_{3}\left[\mathrm{Cr}(\text { oxalate })_{3}\right]

Oxidation state of Cr

Cr + (-2)X3 = -3 

Cr = +3

Chromium is in +3 oxidation state.

So,

The number of unpaired electrons in Cr+3 will be 3.

Ans = 3

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Kuldeep Maurya

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