Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The treatment of H-C\equiv C-H with 2H_2 in presence of Pd produces

Option: 1

Alkane


Option: 2

gem-dihalide


Option: 3

Alcohol


Option: 4

Aldehyde


Answers (1)

best_answer

Dihydrogen gas adds to alkenes and alkynes in the presence of finely divided catalysts like platinum, palladium or nickel to form alkanes. This process is called hydrogenation. These metals adsorb dihydrogen gas on their surfaces and activate the hydrogen–hydrogen bond. Platinum and palladium catalyse the reaction at room temperature but relatively higher temperature and pressure are required with nickel catalysts.

\\\mathrm{CH}_{2}=\mathrm{CH}_{2}+\mathrm{H}_{2} \stackrel{\mathrm{Pt} / \mathrm{Pd} / \mathrm{Ni}}{\rightarrow} \mathrm{CH}_{3}-\mathrm{CH}_{3}\\\mathrm{Ethene\quad\quad\quad\quad\quad\quad\quad \quad \: Ethane}

\\\mathrm{CH}_{3}-\mathrm{C}\equiv \mathrm{C}-\mathrm{H}+2 \mathrm{H}_{2} \overset{\mathrm{Pt/Pd/Ni}}{\longrightarrow} \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\\\mathrm{Propyne \quad\quad\quad\quad\quad\quad\quad\quad \quad \quad \quad Propane}

Therefore, option (1) is correct.

Posted by

rishi.raj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JoSAA 2024 round 4 seat allotment results out at josaa.nic.in; report online by July 15

Latest Question