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The value of b for which the function f(x)=\left\{\begin{array}{cc} 5 x-4, \, \, \, \, \, \, \, 0<x \leq 1 \\ 4 x^2+3 b x, 1<x<2 \end{array}\right. is continuous at every point of its domain, is

Option: 1

-1


Option: 2

0


Option: 3

1


Option: 4

13/3


Answers (1)

best_answer

Consider \mathrm{x}=1, \mathrm{~L}=\mathrm{R}=\mathrm{V}

\Rightarrow 1=4+3 b=1 \\\Rightarrow l=4+3 b=1 \\

\therefore \quad b=-1 .

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Divya Prakash Singh

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