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  • The value of the ‘spin only’ magnetic moment for one of the following configurations in octahedral field is  is 2.84 BM. The correct one is

The value of the ‘spin only’ magnetic moment for one of the following configurations in octahedral field is  is 2.84 BM. The correct one is

Option: 1

d^{4} ( in strong ligand field)


Option: 2

d^{4} ( in weak ligand field)


Option: 3

d^{3} ( in weak as well as in strong fields)


Option: 4

d^{5}  (in strong ligand field)


Answers (1)

best_answer

As we have learnt, 

Magnetic Moments (spin only) is given as 

\sqrt{n\left ( n+2 \right )} where n= number of the unpaired electron.

Number of unpaired e^{-} s and corresponding magnetic moments

\\1\rightarrow 1.7\\2\rightarrow 2.8\\3\rightarrow 3.9\\4\rightarrow 4.9\\5\rightarrow 5.9

 

Thus, for magnetic moment of 2.84 BM, the ion should contain two unpaired electrons

Only in d^{4} with strong field ligand number of unpaired electrons is two.

d^{4} with a weak ligand contains 4 unpaired electrons 

d^{3} contains 3 unpaired electrons irrespective of the strength of the ligand

d^{5} with a strong ligand contains one unpaired electron while that with a weak ligand contains 5 unpaired electrons.

Therefore, option (1) is correct.

Posted by

Kuldeep Maurya

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