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The value of van der waal s constant a for the gases, \mathrm{O}_2, \mathrm{~N}_2, \mathrm{NH}_3$ and $\mathrm{CH}_4 are 1.360,~1.390,~4.170,~2.259 \mathrm{~L}^2 \mathrm{~atm} / \mathrm{mol}^2. The gas which can most easily be liquefied is -

Option: 1

\mathrm{O}_2


Option: 2

\mathrm{~N}_2


Option: 3

\mathrm{NH}_3


Option: 4

\mathrm{CH}_4


Answers (1)

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The ease of liquefication of a gas depend si on theirs intermolecular force of attraction which in fum is measured in terms of vader waal s constant a. Hence, highers the value of a, greater the intermolecular force of attraction, easier the liquefication.
in the present case, \mathrm{NH}_3 has highest a, can most easily be liquefied.

Posted by

Kuldeep Maurya

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