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The variation of applied potential and current flowing through a given wire is shown in figure. The length of wire is 31.4 \mathrm{~cm}. The diameter of wire is measured as 2.4 \mathrm{~cm}. The resistivity of the given wire is measured as x \times 10^{-3} \Omega \mathrm{cm}. The value of \mathrm{x} is ___________.[Take \pi=3.14]

Option: 1

144


Option: 2

22


Option: 3

33


Option: 4

55


Answers (1)

best_answer

\mathrm{\begin{aligned} &\text { slope }=\frac{V}{I}=R=\tan 45^{\circ} \\ &R=1 \Omega \\ &R=\frac{\rho l}{A} \\ &1=\frac{\rho \times 31.4}{\pi r^{2}} \\ &P=\frac{\pi \times(1.2 \mathrm{~cm})^{2}}{31.4 \mathrm{~cm}}=1.44 \times 10^{-1} \\ &x=144 \end{aligned}}

Hence correct answer is 144

Posted by

jitender.kumar

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