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  • The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement (x) starting from mean position to extreme position (A) is given by  </p

The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement (x)
starting from mean position to extreme position (A) is given by
 

Option: 1


Option: 2


Option: 3


Option: 4


Answers (1)

best_answer

\mathrm{K.E=T.E-P.E}

\mathrm{K.E=\frac{1}{2}KA^2-\frac{1}{2}Kx^{2}}

Graph b/w K.E and x will be parabola

Posted by

shivangi.shekhar

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