Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement (x)
starting from mean position to extreme position (A) is given by

Option: 1

Option: 2

Option: 3

Option: 4

Answers (1)

best_answer

$\mathrm{K.E=T.E-P.E}$

$\mathrm{K.E=\frac{1}{2}KA^2-\frac{1}{2}Kx^{2}}$

Graph b/w K.E and x will be parabola

Posted by

shivangi.shekhar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_b of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75

Latest Question