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The velocity of a small ball of mass \mathrm{'m'} and density \mathrm{d_{1}}, when dropped in a container filled with glycerine, becomes constant after some time. If the density of glycerine is \mathrm{d_{2}} , then the viscous force acting on the ball, will be :

Option: 1

\mathrm{mg\left ( 1-\frac{d_{1}}{d_{2}} \right )}


Option: 2

\mathrm{mg\left ( 1-\frac{d_{2}}{d_{1}} \right )}


Option: 3

\mathrm{mg\left ( \frac{d_{1}}{d_{2}}-1 \right )}


Option: 4

\mathrm{mg\left (\frac{d_{2}}{d_{1}}-1 \right )}


Answers (1)

          

\mathrm{B+F_{V}=m g} \\

\mathrm{F_{v}=m g-B} \\                                     

 \because \mathrm{ B=d_{2} v g} \mathrm{=d_{2} \times \frac{m}{d_{1}} g} \\ 

      \therefore \mathrm{F_v=\operatorname{mg}\left(1-\frac{d_{2}}{d_{1}}\right)}

Hence the correct answer is option 2.

Posted by

Ramraj Saini

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