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  • The velocity of an electron in Bohr’s 3rd orbit of hydrogen is x. Then velocity in Bohr’s first orbit of Li2+ is:Option: 1</str

The velocity of an electron in Bohr’s 3rd orbit of hydrogen is x. Then velocity in Bohr’s first orbit of Li2+ is:

Option: 1

x/3


Option: 2

3x


Option: 3

x


Option: 4

9x


Answers (1)

best_answer

 As we have learnt,

The velocity of electron in any orbit is given as:

v_{n}= (2.165\times 10^{6})\frac{z}{n}\: m/s

Thus, velocity of electron in 3rd orbit of hydrogen is (2.165 x 106)/3 = x

Now, velocity of electron in first orbit of Li2+ is (2.165 x 106) x (3/1) = y

Now, on dividing both equations we get:

x/y = 1/9
Thus, y = 9x

Therefore, Option(4) is correct

Posted by

Irshad Anwar

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