Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The vertices of the hyperbola <img alt="\mathrm{9 x^2-16 y^2-36 x+96 y-252=0}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B9%20x%5E2-16%20y%5E2-36%20

The vertices of the hyperbola \mathrm{9 x^2-16 y^2-36 x+96 y-252=0} are 

 

Option: 1

 (6, 3) and (–6, 3)


Option: 2

(6, 3) and (–2, 3)


Option: 3

(–6, 3) and (–6, –3)


Option: 4

none of these


Answers (1)

best_answer

The equation of the hyperbola reduces to \mathrm{\frac{(x-2)^2}{16}-\frac{(y-3)^2}{9}=1}

Posted by

qnaprep

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech Admissions 2025 LIVE: GUJCET registration from December 17; JEE Main, SRMJEEE, BITSAT cut-off updates
anam-khan

JEE Main 2025: NIT Warangal sees increasing demand for emerging fields; BTech cut-offs
anam-khan

BTech Admissions 2025 LIVE: SITEEE, JEE Mains, AEEE exam dates out; MET, SRMJEE registrations underway

Latest Question