The volume of 0.1N dibasic acid sufficient to neutralize 1g of a base that furnishes 0.04 mole of OH− in aqueous solution is:
200 mL
400 mL
600 mL
800 mL
Dibasic acids mean acids have two ionizable hydrogens.
gram eq. of OH- = mole n-factor = 0.04
1 = 0.04
The Law of equivalence we get,
milli equivalents of acid = milli equivalents of base
N1 X V1 (ACID) = ( meq. of base)
0.1×V = ( meq. of base)
0.1 X V = ( meq. of base) = 0.04 1000
V x 0.1 = 40
V = 400ml
Therefore, Option(2) is correct
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