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The volume of gas A is twice than that of gas B .at samw temperature.The pressure of the gases for equal number of moles are -

Option: 1

\mathrm{P_A=2 P_B}


Option: 2

\mathrm{2 P_A=3 P_B}


Option: 3

\mathrm{3 P_A=2 P_B}


Option: 4

None of these


Answers (1)

best_answer

Given, \mathrm{z_A=3 z_B}

Compressibility factor \mathrm{(z)=\frac{P V}{n R T} \text { (for real gases) }}

On substituting in equation we get.

\mathrm{\frac{P_A v_A}{n_A R T_A}=\frac{3 P_B V_B}{n_D R T_B}}--------(1)

Also, it is given tha,

Equation (1) becomes,

\mathrm{v_A=2 v_B, n_A=n_B \text { and } T_A=V_B}

\mathrm{\begin{aligned} & \frac{P_A \times 2 V_B}{n_B R T_B}=\frac{3 P_B V_B}{n_B R T_B} \\ & \Rightarrow 2 P_A=3 P_B \end{aligned}}

Posted by

Devendra Khairwa

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