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  •  The volume versus temperature <img alt="\mathrm{T}" src="https://entrancecorner.oncodecogs.com/g

 The volume \mathrm{V}versus temperature \mathrm{T} graphs for a certain amount of a perfect gas at two pressures \mathrm{P_{1}} and \mathrm{P_{2}} are shown in the figure. Here

Option: 1

\mathrm{P_{1}<P_{2}}


Option: 2

\mathrm{P_{1}>P_{2}}


Option: 3

\mathrm{P_{1}=P_{2}}


Option: 4

can't be


Answers (1)

best_answer

For a perfect gas, \mathrm{PV}=\frac{\mathrm{m}}{\mathrm{M}} \mathrm{RT}

\Rightarrow \quad \mathrm{v}=\frac{\mathrm{mR}}{\mathrm{PM}} \mathrm{RT}
So, the slope of the graph is \frac{\mathrm{mR}}{\mathrm{PM}}

\mathrm{Slope \, \propto \frac{1}{\mathrm{P}}}

\mathrm{Hence \, \mathrm{P}_{1}>\mathrm{P}_{2}}

Hence, (b) is correct

Posted by

Kuldeep Maurya

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