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The work functions of Aluminium and Gold are 4.1 eV and and 5.1 eV respectively. The ratio of the slope of  the stopping potential versus frequency plot for Gold to that of Aluminium is

Option: 1

1


Option: 2

2


Option: 3

1.24


Option: 4

1.5


Answers (1)

best_answer

Using KEmax = eVs = hf – {\phi}0

where {\phi}0 is work function, Vs is stopping potential and f is frequency

\text { or } \mathrm{V}_{\mathrm{s}}=\frac{\mathrm{h}}{\mathrm{e}} \mathrm{f}-\frac{\phi_0}{\mathrm{e}}

therefore the slope m will be same for all graphs and will be independent of {\phi_0}

Posted by

seema garhwal

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