Get Answers to all your Questions

header-bg qa

Three moles of an ideal gas expands reversibly under isothermal condition from 2 L to 20 L at 300 K. The amount of heat-change (in kJ/mol) in the process is:

Answers (1)

\\\Delta U=q+w$ \\\\ Work done in an isothermal reversible process is: \\\\ $w=-n R T \ln \frac{V_{2}}{V_{1}}=-3 \times 8.314 \times 300 \ln \frac{20}{2}=-17232.4 \mathrm{J}$\\\\ As the process of isothermal $\Delta U=0$ \\\\ $q=-w=+17.2 k J$

Posted by

lovekush

View full answer

Similar Questions