Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Three point charges q, -2q and 2q are placed on x-axis at a distance x = 0,  and

Three point charges q, -2q and 2q are placed on x-axis at a distance x = 0, x=\frac{3}{4} and x = R respectively from origin as shown. If q = 2 × 10-6 C and R = 2 cm, the magnitude of net force experienced by the charge -2q is

Option: 1

5440


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \mathrm{F}_{\mathrm{BA}}=\frac{32 \mathrm{kq}^2}{9 \mathrm{q}^2} \quad \mathrm{~F}_{\mathrm{BC}}=\frac{64 \mathrm{kq}^2}{\mathrm{R}^2} \\ & \mathrm{~F}_{\mathrm{B}}=\mathrm{F}_{\mathrm{BC}}-\mathrm{F}_{\mathrm{BA}}=\frac{544 \mathrm{kq}^2}{9 \mathrm{R}^2} \\ & =5440 \mathrm{~N} \end{aligned}

Posted by

vishal kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 Results LIVE: NTA April session result date, time soon; BTech scorecard at jeemain.nta.nic.in
anam-khan

JEE Main 2025 answer key is provisional: NTA says 'drawing conclusions not desirable'
anam-khan

'Students pay for NTA’s mistakes': JEE Main 2025 answer key shows 9 errors, out-of-syllabus questions

Latest Question