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  • Time period of a simple pendulum is T. The time taken to complete  oscillations starting from mean position is <img alt="\frac{\alpha }{\b

Time period of a simple pendulum is T. The time taken to complete \frac{5}{8} oscillations starting from mean position is \frac{\alpha }{\beta }T. The value of \alpha is ____________
Option: 1 7
Option: 2 12
Option: 3 5
Option: 4 11

Answers (1)

best_answer

Total distance covered by the particle=4A.

we divide this whole path in 8 intervals of A/2.

so, 5/8 oscillations means, it has already completed1/2 oscillation(i.e. total dist. = 2A) and is half way to the other side i.e. A/2.

so,\frac{A}{2} = A sin \omega t

\omega = \frac{2 \pi}{T} ,

substitute to get t=T/12.

now, total time taken = time to complete previous one half(2A) + time taken to completeA/2=t/2+t/12=7T/12.

 

So,

\alpha = 7

Posted by

Deependra Verma

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