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To charges repel each other with a force of  200 \mathrm{~N}. one of the charges is increased by  \mathrm{20 \%}  and othen is reduced by  \mathrm{10 \%}  The new repulsive force at same distance would be

Option: 1

200 \mathrm{~N}


Option: 2

216 \mathrm{~N}


Option: 3

300 \mathrm{~N}


Option: 4

316 \mathrm{~N}


Answers (1)

Now,

\mathrm{ f=\frac{q_1 q_2}{x^2}=200 }..........(1)


\mathrm{ q_1^{\prime}=q_1(1+0.2)=1.2 q_1 }


\mathrm{ q_2^{\prime}=q_2(1-0.1)=0 .9 q_2 }

\mathrm{F^{\prime}=\frac{k q_1^{\prime} q_2^{\prime}}{r^2} \Rightarrow \frac{1.08 q_1 q_2 k}{r^2}}


 

Posted by

Ramraj Saini

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