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Total number of 180^{\circ} bond angle in \mathrm{XeO_2F_4} is

Option: 1

12


Option: 2

9


Option: 3

6


Option: 4

3


Answers (1)

As we have learnt,

Xenon dioxytetrafluoride has octahedral geometry and  \mathrm{{sp}^{3} d^{2}} hybridisation. 

 Diagonal bonds are at an angle of 180^{\circ}.

Thus, there are three bonds (\mathrm{O=Xe=O,F-Xe-F,F-Xe-F}) which have 180^{\circ} bond angle.

Therefore, option (4) is correct

Posted by

Kshitij

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