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  • Try this! An aqueous solution of NaCl is marked 10% (w/w). If the density of the solution is 1.071 gmL-1, what is the molality?

An aqueous solution of NaCl is marked 10% (w/w). If the density of the solution is 1.071 gmL-1, what is the molality?

  • Option 1)

    1.85 m

  • Option 2)

    1.90 m

  • Option 3)

    1.95 m

  • Option 4)

    2.0 m

 

Answers (1)

As we have learnt 

 

Molality -

Molality (m) = (number of moles of solute)/(mass of solvent in kg)

 

- wherein

It is defined as the number of moles of solute present in 1 kg of solvent. It is denoted by m.

 

 Weight of salute = 10g

Moles of salute  = \frac{10}{58.5} 

Weight of solvent = 90 g

Molality = \frac{10\times 1000}{58.5\times 90} = 1.90m


Option 1)

1.85 m

Option 2)

1.90 m

Option 3)

1.95 m

Option 4)

2.0 m

Posted by

subam

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