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When XO_{2} is fused with an alkali metal hydroxide in presence of an oxidizing
agent such as KNO_{3} ; a dark green product is formed which disproportionates in
acidic solution to afford a dark purple  solution. X is :

  • Option 1)

    Ti

  • Option 2)

    V

  • Option 3)

    Cr

  • Option 4)

    Mn

 

Answers (1)

best_answer

As we have learned

Color of 'd' block elements complexes -

Generally, d1- d9  electronic configurated metal complex show color according to the 

E=hv

\because \:\:v=\frac{c}{\lambda }, \; E= \frac{hc}{\lambda }

 

MnO_{2}+KOH\rightarrow K_{2}MnO_{4}\xrightarrow[solution]{Acidic}KMnO_{4}

                                \left ( Dark\: Green \right )                    \left ( Dark\: Purple\right )

 

-

 

 


Option 1)

Ti

This is incorrect

Option 2)

V

This is incorrect

Option 3)

Cr

This is incorrect

Option 4)

Mn

This is correct

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Plabita

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