Q

# Try this! - Electrostatics - JEE Main-10

A point dipole $\vec{p}=-p_{0}\hat{x}$ is kept at the origin. The potential and electric field due to this dipole on the y-axis at a distance d are, respectively : ( Take V=0 at infinity)

• Option 1)

$0,\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}$

• Option 2)

$0,\frac{\vec{p}}{4\pi\epsilon _{0}d^{3}}$

• Option 3)

$\frac{\left|\vec{p}\right|}{4\pi\epsilon _{0}d^{2}},\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}$

• Option 4)

$\frac{\left|\vec{p}\right|}{4\pi\epsilon _{0}d^{2}},\frac{\vec{p}}{4\pi\epsilon _{0}d^{3}}$

Views

Electric dipole -

Two equal and opposite charges seperated by small distance.

- wherein

$V=0$

$E=\frac{-k\vec{p}}{r^{3}}$

$\vec{E}=\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}$

Option 1)

$0,\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}$

Option 2)

$0,\frac{\vec{p}}{4\pi\epsilon _{0}d^{3}}$

Option 3)

$\frac{\left|\vec{p}\right|}{4\pi\epsilon _{0}d^{2}},\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}$

Option 4)

$\frac{\left|\vec{p}\right|}{4\pi\epsilon _{0}d^{2}},\frac{\vec{p}}{4\pi\epsilon _{0}d^{3}}$

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