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  2. Try this! - Electrostatics - JEE Main-10
# Engineering

A point dipole \vec{p}=-p_{0}\hat{x} is kept at the origin. The potential and electric field due to this dipole on the y-axis at a distance d are, respectively : ( Take V=0 at infinity)

  • Option 1)

    0,\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}

  • Option 2)

    0,\frac{\vec{p}}{4\pi\epsilon _{0}d^{3}}

  • Option 3)

    \frac{\left|\vec{p}\right|}{4\pi\epsilon _{0}d^{2}},\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}

  • Option 4)

    \frac{\left|\vec{p}\right|}{4\pi\epsilon _{0}d^{2}},\frac{\vec{p}}{4\pi\epsilon _{0}d^{3}}

 

Answers (1)
S solutionqc

 

Electric dipole -

Two equal and opposite charges seperated by small distance.

- wherein

 

 

V=0

E=\frac{-k\vec{p}}{r^{3}}

\vec{E}=\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}                                                                                                                                                                

 

                                                                       


Option 1)

0,\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}

Option 2)

0,\frac{\vec{p}}{4\pi\epsilon _{0}d^{3}}

Option 3)

\frac{\left|\vec{p}\right|}{4\pi\epsilon _{0}d^{2}},\frac{-\vec{p}}{4\pi\epsilon _{0}d^{3}}

Option 4)

\frac{\left|\vec{p}\right|}{4\pi\epsilon _{0}d^{2}},\frac{\vec{p}}{4\pi\epsilon _{0}d^{3}}

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