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  • Try this! In resonance pipe in the fundamental mode, with a tunning fork is 0.1 m. When this length is changed to 0.35 m, the same tunning fork resonates with the first ovetone. Calculate end correction

In resonance pipe in the fundamental mode, with a tunning fork is 0.1 m. When this length is changed to 0.35 m, the same tunning fork resonates with the first ovetone. Calculate end correction

  • Option 1)

    0.012 m

  • Option 2)

    0.025 m

  • Option 3)

    0.05 m

  • Option 4)

    0.024 m

 

Answers (1)

best_answer

Let e be the end correction

\frac{v}{4\left ( l_{1}+e \right )}= \frac{3v}{4\left ( l_{2}+e \right )}\Rightarrow

e= 2.5cm = 0.025m

 

Fundamental frequency with end correction -

\nu _{0}= \frac{V}{4\left ( l+e \right )}     (one end open)

\nu _{0}= \frac{V}{2\left ( l+2e \right )}    (Both end open)

e = end correction

-

 

 


Option 1)

0.012 m

This is incorrect

Option 2)

0.025 m

This is correct

Option 3)

0.05 m

This is incorrect

Option 4)

0.024 m

This is incorrect

Posted by

Aadil

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