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Consider a car moving on a straight road with a speed of 100 m/s he distance at which car can be stopped is $\left [ \mu _{k} = 0.5\right ]$

Option 1)
$100m$

Option 2)
$400\: m$

Option 3)
$800\: m$

Option 4)
$1000\: m$

Answers (1)

best_answer

As we learnt in

Kinetic or Dynamic Friction -

$f_{K}\;\alpha\ R$

$f_{K}=\mu_{K} R$

$f_{K}=$ kinetic friction

$\mu_{K}=$ coefficient of kinetic friction

R = reaction

- wherein

$f_{K}<F_{l}$

$\therefore\ \mu_{K}<\mu_{s}$

$\mu_{K}=$ depends on the nature of surface in contact.

$Retardation\: due\: to\: friction= \mu g$

$\because \nu ^{2}= u^{2}+2as$

$\therefore 0=\left ( 100 \right )^{2}-2\left ( \mu g \right )s$

$or\: \: \: 2\mu gs= 100\times 100$

$or\: \: \: s= \frac{100\times 100}{2\times 0.5\times 10}= 1000\: m$

Correct option is 4.

Option 1)

$100m$

This is an incorrect option.

Option 2)

$400\: m$

This is an incorrect option.

Option 3)

$800\: m$

This is an incorrect option.

Option 4)

$1000\: m$

This is the correct option.

Posted by

prateek

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