Consider a car moving on a straight road with a speed of 100 m/s he distance at which car can be stopped is \left [ \mu _{k} = 0.5\right ]

  • Option 1)

    100m

  • Option 2)

    400\: m

  • Option 3)

    800\: m

  • Option 4)

    1000\: m

 

Answers (1)

As we learnt in

Kinetic or Dynamic Friction -

f_{K}\;\alpha\ R

f_{K}=\mu_{K} R

f_{K}= kinetic friction 

\mu_{K}= coefficient of kinetic friction

R = reaction

- wherein

f_{K}<F_{l}

\therefore\ \mu_{K}<\mu_{s}

\mu_{K}=depends on the nature of surface in contact.

 

 

 

Retardation\: due\: to\: friction= \mu g

\because \nu ^{2}= u^{2}+2as

\therefore 0=\left ( 100 \right )^{2}-2\left ( \mu g \right )s

or\: \: \: 2\mu gs= 100\times 100

or\: \: \: s= \frac{100\times 100}{2\times 0.5\times 10}= 1000\: m

Correct option is 4.


Option 1)

100m

This is an incorrect option.

Option 2)

400\: m

This is an incorrect option.

Option 3)

800\: m

This is an incorrect option.

Option 4)

1000\: m

This is the correct option.

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