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Two travelling waves y_{1} = A\sin[k(x-ct)]  and y_{2} = A\sin[k(x+ct)] are superimposed on a string the distance between adjecent node is 

  • Option 1)

    \frac{ct}{\pi}

  • Option 2)

    \frac{ct}{2\pi}

  • Option 3)

    \frac{\pi}{2k}

  • Option 4)

    \frac{\pi}{k}

 

Answers (1)

best_answer

d is b/w 2 nodes 

X = \frac{\lambda }{2} , k= \frac{2\pi }{\lambda }

Hence X = \frac{\pi }{k}

 

 

Antinode in standing waves -

The position at which the particle is at greatest possible displacement of 2A from equilibrium position.

- wherein

At antinodes

\sin kx= \pm 1

kx= \frac{\pi }{2}, \frac{3\pi }{2}, \frac{5\pi }{2}.........

or\: \: \: x= \frac{n\lambda }{4}

n= 1,3,5.....

 

 


Option 1)

\frac{ct}{\pi}

This is incorrect

Option 2)

\frac{ct}{2\pi}

This is incorrect

Option 3)

\frac{\pi}{2k}

This is incorrect

Option 4)

\frac{\pi}{k}

This is correct

Posted by

Avinash

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