Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Two travelling waves y_{1} = A\sin[k(x-ct)]  and y_{2} = A\sin[k(x+ct)] are superimposed on a string the distance between adjecent node is 

  • Option 1)

    \frac{ct}{\pi}

  • Option 2)

    \frac{ct}{2\pi}

  • Option 3)

    \frac{\pi}{2k}

  • Option 4)

    \frac{\pi}{k}

 

Answers (1)

best_answer

d is b/w 2 nodes 

X = \frac{\lambda }{2} , k= \frac{2\pi }{\lambda }

Hence X = \frac{\pi }{k}

 

 

Antinode in standing waves -

The position at which the particle is at greatest possible displacement of 2A from equilibrium position.

- wherein

At antinodes

\sin kx= \pm 1

kx= \frac{\pi }{2}, \frac{3\pi }{2}, \frac{5\pi }{2}.........

or\: \: \: x= \frac{n\lambda }{4}

n= 1,3,5.....

 

 


Option 1)

\frac{ct}{\pi}

This is incorrect

Option 2)

\frac{ct}{2\pi}

This is incorrect

Option 3)

\frac{\pi}{2k}

This is incorrect

Option 4)

\frac{\pi}{k}

This is correct

Posted by

Avinash

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

FIITJEE blames managing partners for shutdown, warns legal action against poaching of staff
anam-khan

First 3 days of JEE Main 2025: Exam paper analysis, postponement, technical glitches
anam-khan

NTA changes JEE Main 2025 exam centre in Ayodhya due to Maha Kumbh gathering

Latest Question