If a_{1},a_{2},a_{3},..........a_{n} are in A.P. and a_{1}+a_{4}+a_{7}..........+a_{16}=114,

then a_{1}+a_{6}+a_{11}+a_{16} is equal to : 

  • Option 1)

    98

  • Option 2)

    76

  • Option 3)

    38

  • Option 4)

    64

 

Answers (1)

a_{1}+a_{4}+a_{7}+a_{10}+a_{13}+a_{16}=114

a_{1}+a_{16}+a_{4}+a_{13}+a_{7}+a_{10}=114

a_{1}+a_{16}=\frac{114}{3}=38

a_{1}+a_{16}+a_{6}+a_{11}=38+38=76

correct option is (2).


Option 1)

98

Option 2)

76

Option 3)

38

Option 4)

64

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