# The increasing order of the $pK_b$ of the following compound is : Option 1)$(C)< (A)< (D)<(B)$Option 2)$(B)<(D)<(C)<(A)$Option 3)$(A)<(C)<(D)<(B)$Option 4)$(B)<(D)<(A)<(C)$

Inductive effect -

Displacement of $\sigma$ electron towards more electronegative atom is called inductive effect

- wherein

It is a permanent effect

-I - effect (Negative inductive effect) -

Those atoms or group of atoms having more tendency to displace $\sigma$ e - towards itself as compared to Hydrogen atom is called Negative Inductive effect

- wherein

The more the value of $pK_b$, the weaker is the base.

(a)

(F) is withdrawing electrons because of its (-I) effect.

(b)

$\rightarrow \left ( OCH_3 \right )$ will increase the electron density on Nitrogen atom because of its (+M) effect.

(c)

$\rightarrow \left ( NO_2 \right )$ will decrease the electron density upto maximum because of its (-M) effect.

(d)

$\rightarrow \left ( CH_3 \right )$ will increase the electron density on Nitrogen atom because of its (+I) effect.

$\therefore (B)<(D)<(A)<(C)$

Option 1)

$(C)< (A)< (D)<(B)$

Option 2)

$(B)<(D)<(C)<(A)$

Option 3)

$(A)<(C)<(D)<(B)$

Option 4)

$(B)<(D)<(A)<(C)$

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