The increasing order of the pK_b of the following compound is : 

  • Option 1)

    (C)< (A)< (D)<(B)

  • Option 2)

    (B)<(D)<(C)<(A)

  • Option 3)

    (A)<(C)<(D)<(B)

  • Option 4)

    (B)<(D)<(A)<(C)

Answers (1)

 

Inductive effect -

Displacement of \sigma electron towards more electronegative atom is called inductive effect

- wherein

It is a permanent effect

 

 

-I - effect (Negative inductive effect) -

Those atoms or group of atoms having more tendency to displace \sigma e - towards itself as compared to Hydrogen atom is called Negative Inductive effect

- wherein

 

 

 

The more the value of pK_b, the weaker is the base. 

(a)

 

(F) is withdrawing electrons because of its (-I) effect.

(b)

\rightarrow \left ( OCH_3 \right ) will increase the electron density on Nitrogen atom because of its (+M) effect.

(c)

\rightarrow \left ( NO_2 \right ) will decrease the electron density upto maximum because of its (-M) effect.

(d)

\rightarrow \left ( CH_3 \right ) will increase the electron density on Nitrogen atom because of its (+I) effect. 

\therefore (B)<(D)<(A)<(C)


Option 1)

(C)< (A)< (D)<(B)

Option 2)

(B)<(D)<(C)<(A)

Option 3)

(A)<(C)<(D)<(B)

Option 4)

(B)<(D)<(A)<(C)

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