Q

# Try this! - States of matter - JEE Main

An element has BCC ctructure having unit cells 12.08 $\times$ 1023. The number of atoms in these cells is -

• Option 1)

12.08 $\times$ 1023

• Option 2)

24.16 $\times$ 1023

• Option 3)

48.38 $\times$ 1023

• Option 4)

12.08 $\times$ 1022

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Total number of atoms in BCC unit cell = 2

Total number of atoms in $12.08\times 10^{23}\, unit\, cell=2\times 12.08\times 10^{23}$

$=24.16\times 10^{23}$

Effective constituent particles in one unit cell, z -

$z = \frac{n_c}{8} + \frac{n_e}{4} + \frac{n_f}{2} + n_b$

- wherein

Where,

nc = no. of particles at corners in one simple cubic unit cell

ne = no. of particles at edges in one simple cubic unit cell

nf = no. of particles at face centers in one simple cubic unit cell

nb = no. of particles at body center in one simple cubic unit cell

Option 1)

12.08 $\times$ 1023

This is incorrect

Option 2)

24.16 $\times$ 1023

This is correct

Option 3)

48.38 $\times$ 1023

This is incorrect

Option 4)

12.08 $\times$ 1022

This is incorrect

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