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An element has BCC ctructure having unit cells 12.08 \times 1023. The number of atoms in these cells is -

  • Option 1)

    12.08 \times 1023

  • Option 2)

    24.16 \times 1023

  • Option 3)

    48.38 \times 1023

  • Option 4)

    12.08 \times 1022

 

Answers (1)

best_answer

Total number of atoms in BCC unit cell = 2

Total number of atoms in 12.08\times 10^{23}\, unit\, cell=2\times 12.08\times 10^{23}

                                                                                       =24.16\times 10^{23} 

 

Effective constituent particles in one unit cell, z -

z = \frac{n_c}{8} + \frac{n_e}{4} + \frac{n_f}{2} + n_b

- wherein

Where,

nc = no. of particles at corners in one simple cubic unit cell

ne = no. of particles at edges in one simple cubic unit cell

nf = no. of particles at face centers in one simple cubic unit cell

nb = no. of particles at body center in one simple cubic unit cell

 

 


Option 1)

12.08 \times 1023

This is incorrect

Option 2)

24.16 \times 1023

This is correct

Option 3)

48.38 \times 1023

This is incorrect

Option 4)

12.08 \times 1022

This is incorrect

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