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Two blocks of mass 2kg are connected by a massless ideal spring of spring constant k=10N/m. the upper block is suspended from roof by a light string A.The system shown in equilibrium. the string A is now cut,the acceleration (in m/s2)of upper block just after the string A is cut wll be \left ( g=10 m/s^{2} \right )


Option: 1


Option: 2


Option: 3



Option: 4


Answers (1)


Before the string A is cut let x be the elongation in spring for the system in equilibrium ,a=0kx=mg=20N


Just after string A is cut


mg +kx =ma

a=20\: m/s^{2}

Posted by

Gautam harsolia

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