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Two cells are connected between points A and B as shown. Cell 1 has emf of $12 \mathrm{~V}$ and internal resistance of $3 \Omega$ . Cell 2 has emf of $6 \mathrm{~V}$ and internal resistance of $6 \Omega.$ An external resistor R of $4 \Omega$ is connected across $\mathrm{A}$ and $\mathrm{B}$ . The current flowing through $\mathrm{R}$ will be ___________ A.

Option: 1
1

Option: 2
-

Option: 3
-

Option: 4
-

Answers (1)

best_answer

$\\ \frac{1}{r_{e q}}=\frac{1}{r_1}+\frac{1}{r_2} \\ \\\mathrm{r}_{\mathrm{eq}}=\frac{6 \times 3}{6+3}=2 \Omega$

$\\ \frac{E_{e q}}{r_{e q}}=\frac{E_1}{r_1}+\frac{E_2}{r_2} \\ \\ \frac{E_{e q}}{2}=\frac{12}{3}-\frac{6}{6}=4-1=3 \\ \\ E_{e q} = 6 \Omega$

$I=\frac{6}{4+2}=1 A$

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Divya Prakash Singh

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