Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Two coils A and B having turns 300 and 600 respectively are placed near each other. On passing a current of 3.0 ampere in A, the flux linked with A is <img alt="\mathrm{1.2 \times 10^{-4} \mathrm{~

Two coils A and B having turns 300 and 600 respectively are placed near each other. On passing a current of 3.0 ampere in A, the flux linked with A is \mathrm{1.2 \times 10^{-4} \mathrm{~Wb}} and with B it is \mathrm{9.0 \times 10^{-5} \mathrm{~Wb}}. The mutual inductance of the system is:

Option: 1

\mathrm{4 \times 10^{-5} \mathrm{H}}


Option: 2

\mathrm{3 \times 10^{-5} \mathrm{H}}


Option: 3

\mathrm{2 \times 10^{-5} \mathrm{H}}


Option: 4

\mathrm{1.8 \times 10^{-2} \mathrm{H}}


Answers (1)

best_answer

\mathrm{Current \: through \: A, I = 3.0 \mathrm{~A}}

\mathrm{Magnetic\: flux\: linked \: with\: B, \phi=600 \times 9.0 \times 10^{-5} \mathrm{~Wb}}

\mathrm{From, \phi= M}

\mathrm{Mutual\: Inductance, M=\frac{\phi}{I}=\frac{600 \times 9.0 \times 10^{-5}}{3.0}=1.8 \times 10^{-2} \mathrm{H}}

Posted by

Ritika Jonwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NTA Exam Calendar 2025 Live: JEE Main, NEET, CUET schedule to be announced soon; download at nta.ac.in
anam-khan

NTA Exam Calendar 2025: JEE Main, NEET, CUET exam dates soon
anam-khan

JEE Main, NEET, CUET 2025 Dates Live: NTA to announce exam calendar soon on nta.ac.in; latest updates

Latest Question