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Two concentric circular loops of radii \mathrm{\mathrm{r}_{1}=30 \mathrm{~cm}} and \mathrm{\mathrm{r}_{2}=50 \mathrm{~cm}} are placed in \mathrm{\mathrm{X}-\mathrm{Y}} plane as shown in the figure. A current \mathrm{ I=7 A} is flowing through them in the direction as shown in figure. The net magnetic moment of this system of two circular loops is approximately :

Option: 1

\mathrm{\frac{7}{2} \: \hat{k} A m^{2}}


Option: 2

\mathrm{-\frac{7}{2} \: \hat{k} A m^{2}}


Option: 3

\mathrm{7\: \hat{k} \mathrm{Am}^{2}}


Option: 4

\mathrm{-7 \: \hat{k} A m^{2}}


Answers (1)

best_answer

The net magnetic moment \mathrm{=\bar{M}_1+\bar{M}_2}

\mathrm{ { M_{net}} =I A_1(\hat{k})+IA_{2}\left ( \hat{-K} \right )}

\mathrm{\bar{M_{net}}=\left ( 7\times \pi \times 900\times 10^{4}-7\times \pi \times 2500\times 10^{-4} \right )\hat{k}}

            \mathrm{=7\times 1600\times \pi \times 10^{-4}\left ( \hat{k} \right )}

            \mathrm{=35200\times 10^{-4}\left ( \hat{k} \right )}

\mathrm{\bar{M_{net}}\cong -\frac{7}{2}\hat{k}Am^{2}}

Hence (2) is correct option.

Posted by

jitender.kumar

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