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Two equal charges q are placed at a distance of 2a  and a third charge -q  is placed at the midpoint. The potential energy of the system is

Option: 1

-\frac{13}{8\pi\epsilon_0} \frac{q^2}{a}


Option: 2

-\frac{9}{8\pi\epsilon_0} \frac{q^2}{a}


Option: 3

-\frac{5}{8\pi\epsilon_0} \frac{q^2}{a}


Option: 4

-\frac{3}{8\pi\epsilon_0} \frac{q^2}{a}


Answers (1)

best_answer

U_{system} = \frac{1}{4\pi\epsilon_0} \frac{(q)(-q)}{a} + \frac{1}{4\pi\epsilon_0} \frac{(-q)(q)}{a} + \frac{1}{4\pi\epsilon_0} \frac{(q)(q)}{2a} = -\frac{3}{8\pi\epsilon_0} \frac{q^2}{a}

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SANGALDEEP SINGH

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