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  • Two families with 3 members each and one family with 4 members each are to be seated in a row. In how many ways can they be seated so that the same family member are not separated?     Option: 1

Two families with 3 members each and one family with 4 members each are to be seated in a row. In how many ways can they be seated so that the same family member are not separated?
   
Option: 1 2!3!4!
Option: 2 \left ( 3! \right )^{2}\left ( 4! \right )
Option: 3 \left ( 3! \right )\left ( 4! \right )^{3}
Option: 4 \left ( 3! \right )^{3}\left ( 4! \right )

Answers (1)

best_answer

Family A has 3 members they can be arranged in 3! ways

Family B has 3 members they can be arranged in 3! ways

Family C has 3 members they can be arranged in 4! ways

Now A, B, C can be arranged in 3! ways

The total arrangement is \left ( 3! \right )^{3}\left ( 4! \right )

Correct Answer: Option D

Posted by

himanshu.meshram

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