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  • Two identical circular wires of radius 20 cm and carrying current  A are placed in perpendicular

Two identical circular wires of radius 20 cm and carrying current \sqrt{2} A are placed in perpendicular planes as

shown in figure. The net magnetic field at the centre of the circular wires is _________ \times 10^{-8}\mathrm{T}.

Option: 1

628


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \overrightarrow{B_{n e t}}=\frac{\mu_0 i}{2 r} \hat{i}+\frac{\mu_0 i}{2 r} \hat{\jmath} \\ & \Rightarrow B_{\text {net }}=\frac{\mu_0 i}{2 r} \sqrt{2}=4 \pi \times 10^{-7} \times \sqrt{2} \times \sqrt{2} \times \frac{1}{2 \times 0.2}=2 \times 3.14 \times 10^{-6}=628 \times 10^{-8} \mathrm{~T} \end{aligned}

Posted by

Rakesh

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