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Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below : \mathrm{{ }_{1}^{2} X+{ }_{1}^{2} X={ }_{2}^{4} Y}

The binding energies per nucleon for \mathrm{{ }_{1}^{2} X } and  \mathrm{{ }_{2}^{4} Y }are \mathrm{1.1 \: \mathrm{MeV}} and \mathrm{7.6 \: \: \mathrm{MeV}} respectively. The energy released in this process is ____________ \mathrm{\mathrm{MeV}.}

Option: 1

26


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{ { }_1^2 X+{ }_1^2 X \Rightarrow{ }_2^4 Y }
Disintegration energy is the energy released in the process
Energy released\mathrm{=T E_i-T E_f}

\mathrm{=\left ( 2+2 \right )\left ( -1.1 \right )-4\left ( -7.6 \right )}

\mathrm{=26\: MeV}



 

Posted by

Pankaj Sanodiya

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