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Two liquids of equal volume are thoroughly mixed. If their specific heats are C1 and C2 temperature \Theta _{1}, \Theta _{2} and densities d1, d2 respectively. What is the final temperature of the mixture?

Option: 1

\frac{d_{1}c_{1}\Theta_{1}+d_{2}c_{2}\Theta_{2} }{d_{1}\Theta_{1}+d_{2}\Theta_{2}}

 

 

 

 


Option: 2

\frac{c_{1}\Theta_{1}+c_{2}\Theta_{2} }{d_{1}c_{1}+d_{2}c_{2}}


Option: 3

\frac{d_{1}\Theta_{1}+d_{2}\Theta_{2} }{c_{1}\Theta _{1}+c_{2}\Theta _{2}}


Option: 4

\frac{d_{1}c_{1}\Theta_{1}+d_{2}c_{2}\Theta_{2} }{d_{1}c_{1}+d_{2}c_{2}}


Answers (1)

best_answer

 

 

 

 

 \Theta =\frac{m_{1}c_{1}\Theta _{1}+m_{2}c_{2}\Theta _{2}}{m_{1}c_{1}+m_{2}c_{2}}

m_{1}=d_{1}v, \; m_{2}=d_{2}v

\Rightarrow \Theta =\frac{d_{1}c_{1}\Theta_{1}+d_{2}\Theta_{2} c_{2} }{d_{1}c_{1}+d_{2}c_{2}}

 

Posted by

shivangi.bhatnagar

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