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Two parallel glass plates are dipped partly in the liquid of density d keeping them vertical. If the distance between the plates is x, the surface tension for the liquid is T and the angle of contact \theta, then the rise of liquid between the plates due to capillary will be:

Option: 1

\frac{T \cos \theta}{xd}


Option: 2

\frac{2T \cos \theta}{xdg}


Option: 3

\frac{2T}{xdg \cos \theta}


Option: 4

\frac{T \cos \theta}{xdg}


Answers (1)

best_answer

Let the width of each plate be b and due to surface tension, the liquid will rise up to height h, then upward force due to surface tension 

                    = 2Tb \cos\theta

The weight of the liquid rises in between the plate

    = vdg = (bxh) dg

\therefore 2Tb\cos\theta = bxhdg

h = \frac{2T\cos\theta}{xdg}

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vinayak

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