Get Answers to all your Questions

header-bg qa

Two parallel, long wires are kept 0.20 m apart in a vacuum, each carrying a current of x A in the same direction. If the force of attraction per meter of each wire is \mathrm{2 \times 10^{-6}} N, then the value of x is approximately:

Option: 1

\mathrm{1}


Option: 2

\mathrm{2.4}


Option: 3

\mathrm{1.4}


Option: 4

\mathrm{2}


Answers (1)

best_answer

\frac{d F}{d l} =\frac{\mathrm{\mu oI}_{1} I_{2}}{2 \pi d}
        =\frac{4\pi \times 10^{-7}\times x\times x}{2\pi \times 0.2}=2\times 10^{-6}
x =\sqrt{2}=1.4

Hence option 3 is correct
 

Posted by

Ritika Kankaria

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE