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Two parallel straight long conducting wires, which are placed at a distance r from each other, are carrying equal currents i in opposite directions. The value of magnetic induction at a point situated x from one wire in between the wires will be:

 

Option: 1

\frac{\mu_{0}i}{2\pi} [\frac{1}{r-x} - \frac{1}{x} ]


Option: 2

\frac{\mu_{0}i}{2\pi} [\frac{1}{r-x} + \frac{1}{x} ]


Option: 3

\frac{\mu_{0}i}{2\pi (r-x)}


Option: 4

\frac{\mu_{0}i}{2\pi x}


Answers (1)

best_answer

B due to wire 1 at Point P

            = \frac{\mu_{0}i}{2\pi} * \frac{1}{x}

B due to wire 2 at Point P

            = \frac{\mu_{0}i}{2\pi} * \frac{1}{r-x}

So, Bnet at Point P = B1 + B2

        = \frac{\mu_{0} a i}{2\pi} \frac{1}{x} + \frac{\mu_{0} i}{2\pi} \frac{1}{r-x}

        = \frac{\mu_{0} i}{2\pi} [\frac{1}{x} + \frac{1}{r-x}]

Posted by

Divya Prakash Singh

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